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The value of `16^("log"4^(3))`, is
A. 8
B. 3
C. 4
D. 9

1 Answer

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Correct Answer - D
We have,
`16^("log"4^(3)) = 4^(2"log" 4 )""^(3) = 4^("log"4)""^(3^(2)) = 3^(2) = 9`

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