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in Binomial Theorem by (70.6k points)
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The coefficient of `x^2012` in the expansion of `(1 - x)^2008 (1+x+x^2)^2007`, is
A. `""^(2012)C_(2007)`
B. `""^(2012)C_(2008)`
C. `""^(2012)C_(2009)`
D. none of these

1 Answer

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by (71.2k points)
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Best answer
Correct Answer - d
We have,
`(1 - x)^(2008) (1 + x + x^(2))^(2007) = (1 - x) (1 - x^(3))^(2007)`
`= (1 - x^(3))^(2007) - (1 - x^(3))^(2007)`
We find that `x^(2012)` is of the form `x^(3r +2)` where as `(1 - x^(3))^(2007)`
contains terms of the form `x^(3r+1)`. So, there is no term containing `x^(2012)` in the
given expansion.
Hence, cefficient of `x^(2012)` is zero.

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