Question

In ΔABC, AB = 20 cm ∠A = 30°, AC = 12 cm 

a. Find the length of the perpendicular from C to AB. 

b. Find the area of the triangle.

Answer 1

a. Draw CD perpendicular to AB. Angles of ΔADC are 30°, 60°, 90°

CD = 6 cm

b. Area of the triangle = \(\frac{1}{2}\times20\times6=60\)