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A vertex of a square is at the origin and its one side lies along the line 3x-4y-10=0. Find the area of the square.

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A vertex of a square is at the origin and its one side lies along the line 3x-4y-10=0. Find the area of the square.
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Correct Answer - 4 sq.units
Side of the square=length of perp. From of perp. From (0,0) on 3x-4y-10=0
`(|3xx0-4xx10|)/(sqrt(3^(2)(-4)^(2)))=2"units"`
Area of the square=`(2xx2)` sq units=4 sq units
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