Question

In the figure, ∠BAC = 90°, AD = 6cm, CD = 9cm, ∠ACD = x.

a. What is tan x? 

b. How much is ∠BA D 

c. What is the length of BD?

Answer 1

a. \(tanx=\frac{AD}{DC}=\frac{6}{9}=\frac{2}{3}\)

b. x

c. \(\frac{BD}{AD}=\frac{BD}{6}\)

\(\Rightarrow \frac{2}{3}=\frac{BD}{6}\)

\(BD=\frac{2}{3}\times6=4cm\)