Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
154 views
in Mathematics by (71.2k points)
closed by
If A.M. and GM. of roots of a quadratic equation are 8 and 5, respectively, then obtain the quadratic equation.

1 Answer

0 votes
by (70.6k points)
selected by
 
Best answer
Let the required roots be a and b.
Then, `AM=(a+b)/2 rArr (a+b)/2=8 rArr a+b=16` ...(i)
and `GM=sqrt(ab) rArr sqrt(ab)=5 rArr ab=25` ...(ii)
`:.` sum of roots =16 and product of roots `=25`
Hence, the required equation is `x^(2)-16x+25=0`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...