Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
421 views
in Mathematics by (69.1k points)
closed by
The product of the perpendicular from two foci on any tangent to the hyperbola `x^2/a^2-y^2/b^2=1` is (A) `a^2` (B) `(b/a)^2` (C) `(a/b)^2` (D) `b^2`

1 Answer

0 votes
by (67.8k points)
selected by
 
Best answer
The hyperbola is on minor axis=>`y=b`
The two focii are`S_1(ae,0)` and `S_2(-ae,0)`
Let tangent be=>`ax+by+c=0`
Perpendicular length from focii to tangent=>`S_1(b) AND S_2(b)`
Their product=`b^2`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...