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Line joining the points (3,-4) and (-2,6) is perpendicular to the line joining the points (-3,6) and (9,-18).

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Correct Answer - False
Given points are A(3,-4), B(-2,6), P(-3,6) and Q(9,-18)
Now, slope of AB `=(6+4)/(-2-3)=-2`
and slope of PQ `=(-18-6)/(9+3)=-2`
So, line AB is parallel to line PQ.

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