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If H is orthocentre of acute angled triangle ABC, then image of H with respect to side AB always lies on (1) Circumcircle of `triangleABC` (2) Circumcircle of `triangleAHB` (3) Escribed circle opposite to vertex C (4) Circumcircle of `triangleAIB` where `I` is incentve `triangleABC`

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`/_HCF=A+C-90^0`
`/_CHF=180-(A+C)=/_B`
`/_A+/_B+/_C=180`
`In/_ABD` and`/_AID`
HD=ID
`/_ADB=/_ADI`
AD=AD
`/_ABD cong /_AID`
option 1 is correct.

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