Question

A committee of 3 persons is to be constituted from a group of 2 men and 3 women. In how many ways can this be done? How many of these committees would consist of 1 man and 2 women?

Answer 1

`M_1,M_2,W_1,W_2,W_3`
total ways `= .^5C_3 = (5!)/(3!2!)`
`= (5*4*3!)/(3!2*1) = 10`
with 1 man & 2 women
`= .^2C_1.^3C_1`
`= (2!)/(1!1!) * (3!)/(2!1!)`
`=2*3= 6`
answer