Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
5.4k views
in Trigonometry by (67.8k points)
closed by
If `(tanx)/2=(tany)/3=(tanz)/5,x+y+z=pi` and `tan^2x+tan^2y+tan^2z=(38)/K` then K=_________`

1 Answer

0 votes
by (69.1k points)
selected by
 
Best answer
Aas `x+y+z = pi`,
`:. tanx+tany+tanz = tanxtanytanz->(1)`
Let `tanx/2 = tany/3 = tanz/5 = k`
`=>tanx = 2k, tany = 3k, tanz = 5k`
Putting these values in (1),
`2k+3k+5k = 2k(3k)(5k)`
`=>10k = 30k^3`
`=>k^2 = 1/3`
`=>k = 1/sqrt3`
Here, we will not take `k = -1/sqrt3` as it will make `x+y+z` negative.
Now, `tanx = 2/sqrt3 ,tany= 3/sqrt3, tanz = 5/sqrt3`
Now, `tan^2x+tan^2y+tan^2z = 38/K`
`=>4/3+9/3+25/3 = 38/K`
`=>38/3 = 38/K`
`=>K = 3`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...