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If `secx+sec^2x=1` then the value of `tan^8x-tan^4x-2tan^2x+1` will be equal to 0 (b) 1 (c) 2 (d) 3

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If `secx+sec^2x=1` then the value of `tan^8x-tan^4x-2tan^2x+1` will be equal to 0 (b) 1 (c) 2 (d) 3
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`secx+secc^2x=1`
`secx=1-sec^2x=-tan^2x`
Squaring both side
`sec^2x=tan^4x`
`1+tan^2x=tan^4x`
Squaring both side
`(1+tan^2x)^2=tan^8x`
`1+tan^4x+2tan^2x=tan^8x`
`tan^8x-tan^4x-2tan^2x+1=2`.
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