`|sin2x| +|cos2x| = |siny|`
`=>(|sin2x| +|cos2x|)^2 = (|siny|)^2`
`=>sin^2 2x+cos^2 2x +2|sin2xcos2x| = sin^2y`
`=>1+|sin4x| = sin^2y`
`=>1-sin^2y = -|sin4x|`
`=>cos^2y = -|sin4x|`
Now, `cos^2y` will always be positive and `-|sin4x|` will always be negative.
So, only possible value that will satisfy the equation will be when both sides are `0`.
`:. cos^2y = -|sin4x| = 0`
`=>cos y = 0`
So, in the interval `[-2pi,2pi]`,
`=> y = -(3pi)/2,-pi/2,pi/2,(3pi)/2`
So, there `4` values of `y` that saisfies the given equation in the given interval.
