Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
197 views
in Trigonometry by (67.8k points)
closed by
Find all the solution of `4cos^2xsinx-2sin^2x=3sinx`

1 Answer

0 votes
by (69.1k points)
selected by
 
Best answer
`4cos^2xsinx - 2sin^2x = 3sinx`
`=>sinx(4cos^2x - 2sinx -3) = 0`
`=>sinx(4(1-sin^2x) - 2sinx -3) = 0`
`=>sinx(4-4sin^2x - 2sinx -3) = 0`
`=>-sinx(4sin^2x + 2sinx -1) = 0`
`=>-sinx = 0 or 4sin^2x + 2sinx -1 = 0`
`=>sinx = 0 or sinx = (-2+-sqrt(4-4(4)(-1)))/8`
`=>sinx = 0 or sinx = (-1+-sqrt5)/4`
`=>sinx = sin 0^@ or sinx = sin18^@ or sinx = sin (-54^@)`
`=>x = npi or x = npi+(-1)^n(18^@) or x = npi+(-1)^n(-54^@)`
So, these are the three solutions for the given equation.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...