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When `theta=(17pi)/3`, then the value of `(tan theta-cot theta)` is: (a) `2/sqrt3` (2) `-2/sqrt3` (3) `1/(2sqrt3)` (d) None

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`theta=17/3pi=(5+2/3)pi`
`=6pi-pi/3`
`tantheta-cottheta=tantheta-1/tantheta`
`tan(6pi-pi/3)-1/tan(6pi-pi/3)`
`tan(-pi/3)-1/tan9-pi/3)`
`-sqrt3-1/-sqrt3`
`2/sqrt3`
Option B is correct.

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