Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
114 views
in Sets, Relations and Functions by (67.8k points)
closed by
If letters of the word PATANA are arranged in all possible ways as in the dictionary, then the word PATANA from the last is ?

1 Answer

+1 vote
by (69.0k points)
selected by
 
Best answer
`PATANA` consists of `4` letters. Occurance of `P` is `1`.
Occurance of `A` is `3`.
Occurance of `T` is `1`.
Occurance of `N` is `1`.
Now, number of words starting from `A = (5!)/((2!) = 60`
Number of words starting from `N = (5!)/(3!) = 20`
Number of words starting from `PAA = 3! = 6`
Number of words starting from `PAN = (3!)/(2!) = 3`
Number of words starting from `PATAA = 1`
So, total number of words that come before `PATANA = 60+20+6+3+1= 90`
Total number of words that can be formed by the given letters `= (6!)/(3!) = 120`
So, `PATANA` from last is ` = 120-90 = 30`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...