Question

The first order rate constant for the decomposition of CaCO₃ at 700 K is 6.36 x 10^–3 s ^–1 and activation energy is 209 kJ mol^–1 . Its rate constant (in s^–1) at 600 K is x × 10^–6 . The value of x is ........ (Nearest integer)

[Given R = 8.31 J K^–1 mol^–1 ; log 6.36 x 10^–3 = –2.19, 10^–4.79 = 1.62 x 10^–5]

Answer 1

Answer is 16

⇒ K₆₀₀ = 10^-4.79 = 1.62 x 10^-5

= 16.2 x 10^-6

= X x 10^-6

⇒x = 16