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When 5.1 g of solid NH4HS is introduced into a two litre evacuated flask at 27°C, 20% of the solid decomposes into gaseous ammonia and hydrogen sulphide. The Kp for the reaction at 27°C is x × 10–2 . The value of x is ........ (Integer answer)

[Given R = 0.082 L atm K–1 mol–1]

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Answer is 6

moles of NH4HS initially taken = \(\frac{5.1\,g}{51g\,mol}\) 

= 0.1 mol

volume of vessel = 2l

= 6.05 x 10-2

⇒ 6

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