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Find the greatest number of four digits which is exactly divisible by 15, 24 and 36.

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Prime factorization: 

15 = 3 × 5 

24 = 23 × 3 

36 = 22 × 32 

LCM = product of greatest power of each prime factor involved in the numbers = 23 × 32 × 5 = 360 

Now, the greatest four digit number is 9999. 

On dividing 9999 by 360 we get 279 as remainder. 

Thus, 9999 – 279 = 9720 is exactly divisible by 360. 

Hence, the greatest number of four digits which is exactly divisible by 15, 24 and 36 is 9720.

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