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If `f(x)=cos^(2)x+sec^(2)x`, then

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If `f(x)=cos^(2)x+sec^(2)x`, then
A. f(x) `lt`1
B. f(x) = 1
C. 2`lt`f(x)`lt`1
D. f(x)`ge`2
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Correct Answer - D
Given that, `f(x) =cos^(2)x+sec^(2)x`
We know that, AM`ge`GM
`" "(cos^(2)x+sec^(2)x)/(2)gesqrt(cos^(2)x*sec^(2)x)` ltBrgt `rArr" "cos^(2)x+sec^(2)xge2" "[becausecosx*secx= 1]`
`rArr" "f(x)ge2`
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