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`cos2thetacos2phi+sin^2(theta-phi)-sin^2(theta+phi)=`

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`cos2thetacos2phi+sin^2(theta-phi)-sin^2(theta+phi)=`
A. `sin2(theta+phi)`
B. `cos2(theta+phi)`
C. `sin2(theta-phi)`
D. `cos2(theta-phi)`
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1 Answer

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Correct Answer - B
Given expression, `cos2thetacos2phi+sin^(2)(theta-phi)-sin^(2)(theta+phi)`
`" "=cos2theta*cos2phi+sin(theta-phi+theta+phi)*sin(theta-phi-theta-phi)`
`" "=cos2theta*cos2phi-sin2theta*sin2phi`
`" "=cos(2theta+2phi)=cos2(theta+phi)`
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