Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
381 views
in Trigonometry by (70.1k points)
closed by
The maximum distance of a point on the graph of the function `y = sqrt 3 sin x + cos x` from X-axis is

1 Answer

0 votes
by (73.5k points)
selected by
 
Best answer
Given that, `y = sqrt(3)sinx+cosx`
`" "y=2[(sqrt(3))/(2)sinx+(1)/(2)cosx]`
`" "=2[sinx*cos""(pi)/(6)+cosxsin""(pi)/(6)]`
`" "=2sin(x+pi//6)`
Graph of y = `2sinx`
image
Hence, the maximum distance is 2 units.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...