Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
312 views
in Mathematics by (70.1k points)
closed by
`lim_(xto(pi)) (1-sin(x/2))/(cosx/2(cosx/4-sinx/4))`

1 Answer

0 votes
by (73.5k points)
selected by
 
Best answer
Given, `underset(xto(pi))"lim"(1-sin(x/2))/(cosx/2(cosx/4-sinx/4))`
`=underset(xto(pi))"lim"(cos^(2)x/4 + sin^(2)x/4-2.sinx/4.cosx/4)/(cosx/2.(cosx/4-sinx/4))` `[therefore sin^(2)theta+cos^(2)theta=1sin2theta=2sinthetacostheta]`
`=underset(xto(pi))"lim"(cosx/4-sinx/4)^(2)/((cos^(2)x/4-sin^(2)x/4)(cosx/4)-sin(x/4))` `[therefore cos^(2)2theta=cos^(2)theta-sin^(2)theta]`
`=underset(xto0)"lim"((cos(x/4)-sin(x/4))/((cosx/4+sinx/4)(cosx/4-sinx/4)))` `[therefore a^(2)-b^(2)=(a+b)(a-b)]`
=`underset(xto(pi))"lim"1/(cosx/4+sin x/4)=1/(1/sqrt(2)+1/sqrt(2))=sqrt(2)/2=1/sqrt(2)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...