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हल करें (i) `tan theta +tan 2 theta+sqrt(3) tan theta. 2 theta=sqrt(3)` (ii) `tan x+2tanx+tanx.tan2x=1` (iii) `tanx+tan4x+tan7x=tanx.tan7.x` (iv) `tan

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हल करें
(i) `tan theta +tan 2 theta+sqrt(3) tan theta. 2 theta=sqrt(3)`
(ii) `tan x+2tanx+tanx.tan2x=1`
(iii) `tanx+tan4x+tan7x=tanx.tan7.x`
(iv) `tanx+tan2x+tan3x=tan.tan2x.tan3x.`
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Correct Answer - `(i) (1)/(9)(3n+1) pi, n in I, " " (ii) (4n+1)(pi)/(12)n in I`
`(iii) (npi)/(12)n in I" " (iv) (n pi)/(6)n, in I`
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