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उस सरल रेखा का समीकरण ज्ञात कीजिए जिस पर मूल बिन्दु से डाले गये लम्ब कि लम्ब x -अक्ष से `135 ^(@)` का कोण बनाता है ।

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मूल बिन्दु से डाले गए लम्ब की लम्बाई , p =7 ,
तथा x -अक्ष से झुकाव `theta =135 ^(@)`
तब समीकरण ,
`x cos theta + y sin theta =p`
`x cos 135 ^(@) + y sin 135^(@) =7`
`-x xx(1)/(sqrt(2))+yxx(1)/(sqrt(2))=7`
`-x+y=7sqrt(2)`
`-x+y-7sqrt(2)=0`
या `x-y+7sqrt(2)=0.`

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