We know that the lengths of the two tangents from an exterior point to a circle are equal.

CA = CE, DB = DE and PA = PB Now,
the perimeter of = PC + CD + DP
= PC + CE + ED + DP
= PC + CA + DB + DP
= PA + PB = 2PA(PB = PA)
Thus, the perimeter of ∠PCD = 2 × 25 = 50cm