If the line which contains the points (x1, y1), (x3, y3) also contains (x, y), then
\(\frac{y-y_1}{x-x_1}=\frac{y_3-y_1}{x_3-x_1}=\frac{2d}{2d}=1\)
y - y1 = 1
y = 1 + y1
x - x1 = 1
x = 1 + x1
The point (x, y) is one greater than (x1,y1)
Therefore, (x1, y1), (x2, y2) …………. will be in the same line