Question

How many moles of Cl₂  present in 11.2 L of same in STP? Find out the mass of this?

Answer 1

No.of moles present in 11.2 litre of chlorine = \(\frac{11.2}{22.4}\) = 0.5 mol

Mass of 0.5 moles of chlorine = 0.5 × 35.5 = 17.759 g.