Question

Write down the preparation of 100 ml NaOH solution of 0.1 M.

Answer 1

GMM of NaOH = 40 g

Molarity = \(\frac{Number\,of\,moles\,of\,solute}{Volume\,of\,solution\,in\,litres}\) = \(\frac{n}{v}\) 

M = 0.1 V=100ml = 0.1 L 

0.1 = n/0.1 

∴ n = 0.1 × 0.1 = 0.01

Mass needed to prepare 100 ml NaOH in 

0.1M = 0.01 × 40 = 0.4g 

Take 0.4 g NaOH in a beaker. Dissolve it Hilly by adding a little amount of water. 

Then, again add water to make it 100 ml.