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Prove that: `(cos7A+cos5A)/(sin7A-sin5A)=cotA`

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Prove that:
`(cos7A+cos5A)/(sin7A-sin5A)=cotA`
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LHS `=(cos7A-cos5A)/(sin7A-sin5A)`
`=(2cos(7A+5A)/(2). Cos(7A-5A)/(2))/(2cos(7A+5A)/2.sin(7A-5A)/(2))`
`=cosA/(sinA)=cotA=RHS` Hence Proved
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