Correct Answer - A
If plant cell happens to be bathed in hypertonic solution, it loses water through the process of exosmosis. The loss of wate is first from cytoplasm and then central vacuole. As a result, the protoplast is reduced in size. This decreases turgor pressure or pressure potential `(psi_(p))` and corresponding wall pressure. solute potentail becomes slightly more negative due to loss of water. The cell attains a minimum size when turgor pressure is zero/pressure potential `(psi_(p))` is zero.
Therefore, `psi_(w) = psi_(s) + psi_(p)`
or `psi_(w) = psi_(s) (as psi_(p) = 0)`
A cell which is deficient in turgor is called flaccid.
