Question

If a body of mass 40 kg is kept at a distance of 0.5 m from a body of mass 60 kg, what is the mutual force of attraction between them?

Answer 1

F = \(\frac{Gm_1m_2}{d^2}\)

m₁ = 40 kg,

m₂ = 60 kg,

d = 0.5 m

= \(\frac{G\times40\times60}{(0.5)^2}\)

= \(\frac{G\times 2400}{0.25}\)

= \(\frac{6.67\times10^{-11}\times2400}{0.25}\)

= 64032 x 10^-11

= 6.4032 x 10^-7N