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Each hydrogen atom is excited by giving 10.2eV. The maximum number of spectral lines in the emission is equal to
A. 1
B. 2
C. 3
D. 4

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Correct Answer - A
`E_(2) -E_(1) = 10.2ev`, so electron is excited to second orbit, therefore no of spectral lines `=(n(n-1))/(2)`

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