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The ration of the `"e//m"` (specific charge) values of an electron and an `alpha-"particle"` is
A. `2 : 1`
B. `1 : 1`
C. `1 : 2`
D. None of these

1 Answer

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Best answer
Correct Answer - D
(d) `((e//m)_e)/((e//m)_alpha) = (e//m_e)/(2e//4 xx 1836 m_e)`.

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