Question

Calculate the momentum of a moving particle which has a wavelength of `200 nm`

Answer 1

Wavelength of particle `= 200 nm = 200 xx 10^(-9) m`
According to de Broglie relationship
`lambda = (h)/(P)`
`Momentum P = (h)/(lambda)= (4.626 xx 10^(-34)J s)/(200 xx 10^(-9)m)= 3.313 xx 10^(-27) kg m s^(-1)`