Question

Draw the two quadrilaterals shown below, in your note book. Draw tri-angles of the same area and calculate the areas (The lengths needed may be measured).

Answer 1

1.

In the given figure, a line parallel to BD through C and AB produced intersect at E. Now area of ∆AED is equal to the area of quadrilateral. Measure the required lengths and then find the area.

AE = 10.8 cm

Height from D to AE = 2.9 cm

Area of ∆ AED = \(\frac{1}{2}\times10.6\times2.9\)

= 15.66 sq.cm

2.

In the given figure, a line parallel to BD through C and AB produced intersect at E. Now area of ∆ AED is equal to the area of quadrilateral. Measure the required lengths and then find the area. AE = 12.6 cm DP = 5.2 cm Area of ∆ AED = \(\frac{1}{2}\) x AE X PD

= \(\frac{1}{2}\) x 12.6 x 5.2 = 32.76 sq cm