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`4` moles of A are mixed with `4` moles of B, when `2` moles of C are formed at equilibrium according to the reaction `A+B hArr C+D`.
The value of equilibrium constant is
A. `(1)/(4)`
B. `(1)/(2)`
C. `1`
D. `4`

1 Answer

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Best answer
Correct Answer - C
`{:(,,A,+,B,hArr,C,+,D),("Initial conc.",,4,,4,,0,,0),("After T time conc.",,(4-2),,(4-2),,2,,2):}`
Equilibrium constant `= ([C][D])/([A][B]) = (2xx2)/(2xx2) = 1`

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