Question

The reaction quotient (Q) for the reaction `N_(2)(g) + 3H_(2)(g)hArr2NH_(2)(g)` is given by Q `= ([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))`. The reaction will proceed towards right side if
where `K_(c)` is the equilibrium constant.
A. `Q gt K_(c)`
B. `Q = 0`
C. `Q = K_(c)`
D. `Q lt K_(c)`

Answer 1

Correct Answer - A
`N_(2)(g) + 3H_(2)(g)hArr2NH_(3)(g)`
`.:` (Quotient) `=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))` , `Delta n = 2-4 = -2`
At equilibrium Q is equal to `K_(c)` but for the progress of reaction towards right side `Q gt K_(c)` .