Correct Answer - A
`K_(1) = ([NO_(2)])/([NO][O_(2)])` and `K_(2) = ([NO]^(2)[O_(2)])/([NO_(2)]^(2))`
If eqn. is multiplied by n, then new equilibrium constant is `K_(1)n` and if equ. Is reversed, then new equilibrium constant is reciprocal of pervious.
`:. K_(2) = (1)/(K_(1)^(2))`