Question

For the reaction `A_(2)(g) + 2B_(2)hArr2C_(2)(g)` the partial pressure of `A_(2)` and `B_(2)` at equilibrium are `0.80` atm and `0.40` atm respectively.The pressure of the system is `2.80` atm. The equilibrium constant `K_(p)` will be
A. 20
B. `5.0`
C. `0.02`
D. `0.2`

Answer 1

Correct Answer - A
`A_(2)(g)+2B_(2)(g)hArr2C_(2)(g)`
`P_(A_(2))= 0.80` atm
`P_(B_(2)) = 0.4` atm
Total pressure of the system `=2.8` atm
`:. P_(C_(2)) =2.8 -0.8 -0.4 =1.6`
`K_(p) =(P_(C_(2))^(2))/(P_(A_(2))xxP_(B_(2))^(3)) = ((1.6)^(2))/(0.8xx(0.4)^(2)) =20`