Question

When sulphur ( in the form of `S_(B))` is heated at temperature `T`, at equilibrium , the pressure of `S_(B)` falls by `30%` from `1.0 atm`, because `S_(B)(g)` in partially converted into `S_(2)(g)`.
Find the value of `K_(P)` for this reaction.
A. `2.96`
B. `6.14`
C. `204.8`
D. None of these

Answer 1

Correct Answer - 1
`K_(p)=(P_(S_(2)(g))^(2))/(P_(S_(8)(g)))=((4xx0.3)^(4))/(0.70)=2.96`