Question

For the system `3A + 2BhArr` C, the expression for equilibrium constant is
A. `([3A][2B])/(C)`
B. `([C])/([3A][2B])`
C. `([A]^(3) [B]^(2))/([C])`
D. `([C])/([A]^(3) [B]^(2))`

Answer 1

Correct Answer - D
Equilibrium constant for the reaction, `3A + 2Bh C` is
`K= ([C])/([A]^(3) [B]^(2))`