Question

One mole of a compound AB reacts with 1 mole of a compound CD according to the equation `AB + CD hArr AD + CB`.
When equilibrium had been established it was found that `(3)/(4)` mole each of reactant AB and CD has been converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction is
A. `(9)/(16)`
B. `(1)/(9)`
C. `(16)/(9)`
D. 9

Answer 1

Correct Answer - D
`AB + CDhArr AD + CD`
mole at t = 0 ,1,1,0,0
Mole at equilibrium `(1-3/4)(1-3/4)hArr(3/4)(3/4)`
`0.25` `0.25` `0.75` `0.75`
`K_(c) = (0.75xx0.75)/(0.25xx0.25) = (0.5625)/(0.0625) = 9`