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For the reaction `H_(2)(g) + I_(2)(g)hArr2HI(g)` at 721 K the value of equilibrium constant `(K_(c))` is 50. When the equilibrium concentration of both is `0.5` M, the value of `K_(p)` under the same condtions will be
A. `0.002`
B. `0.2`
C. `50.0`
D. `50//RT`

1 Answer

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Best answer
Correct Answer - C
For the reaction `H_(2) + I_(2)hArr 2HI`
`Delta n = 0`
So `K_(p) = K_(c) :. 50.0`

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