Question

The value of `K_(c)` for the reaction:
`A_(2)(g)+B_(2)(g) hArr 2AB(g)`
at `100^(@)C` is `49`. If `1.0 L` flask containing one mole of `A_(2)` is connected with a `2.0 L` flask containing one mole of `B_(2)`, how many moles of AB will be formed at `100^(@)C`?

Answer 1

Correct Answer - A
`{:(,A_(2),+,B_(2),hArr,2AB),("Initial",1,,2,,),("Total",V=1+2=3,,,,),("At equlibrium",(1-x)/3,,(2-x)/3,,(2x)/3):}`
`K=50=((2x//3)^(2))/(((1-x)/3)((2-x)/3))`
`x=7/9 "mol"`
Number of moles of `AB` formed at equilibrium `=14/9=1.55 "moles"`