Question

The equilibrium constant `K_(p)` for a homogeneous gaseous reaction is `10^(-8)`. The standard Gibbs free energy change `DeltaG^(ɵ)` for the reaction `("using" R=2 cal K^(-1) mol^(-1))` is
A. `10.98 kcal`
B. `-1.9 kcal`
C. `-4.1454 kcal`
D. `+4.1454 kcal`

Answer 1

Correct Answer - A
`DeltaG^(ɵ)=-2.303 RT log K`
`=-2.303xx2xx298 log 10^(-8)`
`=-2.303xx2xx298xx-8 cal`
`=10980 cal=10.98 kcal`