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Calculate the pressure of `CO_(2)` gas at `700 K` in the hetrogeneous equilibrium reaction `CaCO_(3)(s) hArr CaO(s)+CO_(2)(g)`, if `DeltaG^(ɵ)` for this reaction is `130.2 kJ mol^(-1)`.

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Correct Answer - A::D
Here `K_(p)=P_(CO_(2))`
Also, `DeltaH^(ɵ)=-RT ln K_(p)`
`:. ln K_(p)=(DeltaG^(@))/(RT)=(130.2xx10^(3) J "mol"^(-1))/((8.314 J K^(-1) "mol"^(-1))(700 K))`
`:. P_(CO_(2))=K_(p)=1.94xx10^(-10) "atm"`

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