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What should be the number of moles of `H_(2)` in `0.224 L` of `H_(2)(g)` at `STP(273 K,1 atm)`? Assume the gas to behave ideally.
A. `0.001`
B. `0.1`
C. `1.0`
D. `0.01`

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Correct Answer - D
`n_(H_(2))` = Volume of `H_(2)(g)` of` "STP"//22.4 L "mol"^(-) = 0.224`
`L//22.4 L "mol"^(-) = 0.01 "mol"`

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