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The volume occupied by `7.40 g of CO_(2)` (at `STP`) is
A. `3.8 L`
B. `4.5 L`
C. `5.6 L`
D. `2.9 L`

1 Answer

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Best answer
Correct Answer - A
Since `1 mol` of an ideal gas occupies `22.4 L at STP`, we have
`V_(CO_(2)) = (n_(CO_(2))) (22.4 (L)/(mol))`
`= ((7.40 g)/(44 g mol^(-1))) (22.4 L mol^(-1))`
`= 3.76 L`

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