Question

Exactly `100 mL` of oxygen is collected over water of `23^(@)C` and `800 mm` pressure. Calculate the volume of dry oxygen at `NTP`. (Vapour pressure of water at `23^(@)C` is `21 mm`.)

Answer 1

`{:(V_(1)= 100 mL, V_(2)=?),(P_(1)=729 mm, P_(2)=760mm),(T_(1)=23^(@)C=23+273=296K, T_(2)=273K):}`
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
`V_(2)=(P_(1)V_(1)T_(2))/(P_(2)T_(1))=(779xx100xx273)/(760xx296)=94.54 mL`